x^2+64x+240=0

Solution for x^2+64x+240=0 equation:

x^2+64x+240=0

a = 1; b = 64; c = +240;
Δ = b2-4ac
Δ = 642-4·1·240
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-56}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+56}{2*1}=\frac{-8}{2}
=-4
$